19=49x^2-6

Solution for 19=49x^2-6 equation:

19=49x^2-6

We move all terms to the left:

19-(49x^2-6)=0

We get rid of parentheses

-49x^2+6+19=0

We add all the numbers together, and all the variables

-49x^2+25=0

a = -49; b = 0; c = +25;
Δ = b2-4ac
Δ = 02-4·(-49)·25
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-70}{2*-49}=\frac{-70}{-98}
=5/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+70}{2*-49}=\frac{70}{-98}
=-5/7
$